![]() ![]() When the optocoupler transistor is on, the mosfet gate charges through R15 and will quickly gain full charge and have no current, meaning we will have (5 - Vforward transistor), ( 5 - 0.7V) = 4.3V or so on the gate, Correct? When the optocoupler transistor is off, the gate of the mosfet goes to ground, through the 2 resistors, shutting it off, so power loss on the 5V or uC failure means mosfet = off. The reason I did the schematic that way (correct me if I am wrong I am still new at this) ![]() I think it would be equivalent to the one I put in my schematic, except for the base. The optocoupler I am going to use is a PS2501-4A, 16 pin, 4 channels.The mosfets I am going to use are similar but not the one on the schematic: Either FQP30N06L or AOI518 ( both logic level N channel, 2.6V max Vgs(th) ). ![]()
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